4x^2+4=292

Solution for 4x^2+4=292 equation:

4x^2+4=292

We move all terms to the left:

4x^2+4-(292)=0

We add all the numbers together, and all the variables

4x^2-288=0

a = 4; b = 0; c = -288;
Δ = b2-4ac
Δ = 02-4·4·(-288)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{2}}{2*4}=\frac{0-48\sqrt{2}}{8}
=-\frac{48\sqrt{2}}{8}
=-6\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{2}}{2*4}=\frac{0+48\sqrt{2}}{8}
=\frac{48\sqrt{2}}{8}
=6\sqrt{2}
$